sekarang kita gambarkan diagram gaya-gaya dalamnya,

di potongan 1, antara ujung balok sebelah kiri sampai perletakan sendi.

ΣFx = 0

Nx = 0



ΣFy = 0

Vx = 0



ΣM = 0

-M - Mx = 0

-4 - Mx = 0

Mx = -4 satuan






dipotongan dua, antara sendi dan rol,

ΣFx = 0

Nx + Ha = 0

Nx + 2 = 0

Nx = -2 satuan




ΣFy = 0

Va - (q)(x) - Qx = 0

1.66795 - (1.2)(x) - Qx = 0

Qx = 1.66795 - 1.2x

Qx = 1.66795 - 1.2x = 0

x = 1.38996 satuan

Q(0) = 1.66795 - 1.2(0) = 1.66795 satuan

Q(4) = 1.66795 - 1.2(4) = -3.13205 satuan



ΣM = 0

-M + (Va)(x) - 0.5(q)x^2 - Mx = 0

-4 + (1.66795)(x) - 0.5(1.2)x^2 - Mx = 0

Mx = -0.6x^2 + 1.66795x - 4

Mx = -0.6x^2 + 1.66795x - 4 = 0

M(0) = -0.6(0)^2 + 1.66795(0) - 4 = -4 satuan

M(4) = -0.6(4)^2 + 1.66795(4) - 4 = -6.9282 satuan





di potongan antara rol dan ujung balok sebelah kanan,

amati potongan dari sebelah kanan

ΣFx = 0

Nx + P1 cos 60 = 0

Nx + 4 cos 60 = 0

Nx = -2 satuan



ΣFy = 0

Qx - P1 sin 60 = 0

Qx - 4 sin 60 = 0

Qx = 3.4641 satuan




ΣM = 0

Mx + (P sin 60)(x) = 0

Mx + (4 sin 60)(x) = 0

Mx = 3.4641x

M(0) = 3.4641(0) = 0

M(2) = 3.4641(2) = 6.9282 satuan


sehingga sketsa diagram gaya-gaya dalamnya adalah: