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Membalas thread gareszt_encrew bisa dibuktikan sendiri (paling cepat dengan vektor posisi), DC = AB - 2EF DC = 14 - 2(4) DC = 6 cm itu DC = AB - 2EF kasih tau dong cara pendapatan rumusnya itu :bingung sama cara vektornya jga dong gan :)
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew http://latex.codecogs.com/gif.latex?%5Cdpi%7B100%7D%20%5C%5C%5E4%20%5Clog%20%5Cleft%20%28%5E3%20%5Clo g%20%282x-7%29%20%5Cright%20%29%20%3D%200%5C%5C%5C%5C%20%5Cfrac%7B%5Clog%20%5Cleft%20 %28%5Cfrac%7B%5Clog%20%282x-7%29%7D%7B%5Clog%203%7D%20%5Cright%20%29%7D%7B%5Clog%204%7D%20%3D%200%5C%5C %5... 
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew http://latex.codecogs.com/gif.latex?%5Cdpi%7B100%7D%20%5C%5C%5E4%20%5Clog%20%5Cleft%20%28%5E3%20%5Clo g%20%282x-7%29%20%5Cright%20%29%20%3D%200%5C%5C%5C%5C%20%5Cfrac%7B%5Clog%20%5Cleft%20 %28%5Cfrac%7B%5Clog%20%282x-7%29%7D%7B%5Clog%203%7D%20%5Cright%20%29%7D%7B%5Clog%204%7D%20%3D%200%5C%5C %5...
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew gak apa-apa akarnya gede, kan ada kalkulator... 5n² + 11n - 2436 = 0 5n² + 116n - 105n - 2436 = 0 n(5n + 116) - 21(5n + 116) = 0 (n - 21)(5n + 116) = 0 tapi klo misalnya lagi disekolah gitu kan repot ga bisa make kalkulator ._. Klo ini ^4 log (^3 log (2x-7)) = 0 Bisa lgsg jadi gini ,
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew Klo ini ^4 log (^3 log (2x-7)) = 0 Bisa lgsg jadi gini , crnya gimana ? :bingungs log (log (2x-7)/log 3)/log 4 = 0 log (2x-7)/log 3 = 1 :bingung up up :bingung::bingung: sekalian deh mau nanya yg laen , ada cara cepet ga nyari pemfaktoran 5n² + 11n - 2436 = 0 ? difaktorin biasa yg kyk gini .......
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew mungkin maksudnya : ^4 log (^3 log (2x-7)) = 0 log (log (2x-7)/log 3)/log 4 = 0 log (2x-7)/log 3 = 1 2x - 7 = 3 x = 5 Klo ini ^4 log (^3 log (2x-7)) = 0 Bisa lgsg jadi gini , crnya gimana ? :bingungs log (log (2x-7)/log 3)/log 4 = 0 log (2x-7)/log 3 = 1 :bingung
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew http://latex.codecogs.com/gif.latex?%5Cdpi%7B100%7D%20%5C%5C%5Ctext%7Bbukan%20begitu%20maksudnya..... ...penyebut%20yang%20ane%20tulis%20adalah%7D%5C%5C%5C%5C%202%5Clog%202%20%5 Ctext%7B%20%5Ctextbf%7Bbukan%20%7D%20%7D%20%5E2%5Clog%202 Owh iya yah ane kebalik disitunya , klo log 4 itu = log 2^2 
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew bukan begitu maksudnya, Neng.... lihat lagi di sini kalo ditulis ulang dengan latext jadinya begini: http://latex.codecogs.com/gif.latex?%5C%5C%5Cfrac%7B%5Clog%203%20+%20%5Clog%202%7D%7B2%5Clog%202%7D%3 Dm+1%5C%5C%5C%5C%20%5Ctext%7Bkedua%20ruas%20dikali%202%2C%20sehingga....... % 
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew (log 3 + log 2)/(2 log 2) = m + 1 Kedua ruas dikali 2, (log 3 + log 2)/ log 2 = 2(m + 1) log 3/log 2 + log 2/log 2 = 2m + 2 log 3/log 2 + 1 = 2m + 2 jadi 2 . ( log 3 + log 2 ) itu = ( log 3 + log 2 ) / log 2 ? http://s.kaskus.id/images/2014/01/14/5842072_20140114073939.jpg 
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew ^4 log 6 = m + 1 log 6/log 4 = m + 1 (log 3 + log 2)/(2 log 2) = m + 1 log 3/log 2 + 1 = 2m + 2 log 3/log 2 = 2m + 1 u = ^9 log 8 u = 3 log 2/(2 log 3) u = (3/2)(1/(2m + 1) u = 3/(4m + 2) Itu (log 3 + log 2)/(2 log 2) = m + 1 Bisa langsung jadi log 3/log 2 + 1 = 2m + 2 dr mana gan ?
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew bantu ane ajarin logaritma ama trigono dong gan :D ane masih kelas 3 smp sih tp seneng aja belajar materi" SMA :D minta koreksi gan , soalnya ane kerjain jawabannya ga sesuai dikunci jwbanny 1. 7log9=n , maka nilai 343 log 81 = ? a.2/3n b.3/2n c.2n d.3n e.(343/81)n 7 log 3² = n 2 . 7lo 
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
Membalas thread gareszt_encrew itu kan data hasil percobaan, diambil rata"nya. V total = 8.3, V rata" = 2.075 I total = 0.543 A, I rata" = 0.13575 A R = V rata"/ I rata" = 2.075 / 0.13575 = 15.2 betul ga ya :ngacir: Terlalu sulit itu itungannya klo ane coba jumlahin semua hambatannya ( 60,98
PROBLEM SOLVING - tempat bertanya PR Kaskuser (SD, SMP, SMA) - Part 3
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